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Question

Electric Potential on the surface of a charged spherical shell of radius 10 cm is 50 volt. Find the value of electric potential at a distance of 20 cm from the center of spherical shell.

Solution
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Potential at surface = 50 V
V=K.QR
50=K.Q0.1
KQ= 5
potential at 200 m from centre
V=K.Qr
V=50.2 = 25 volt
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