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Electrical potential in an electric field is given by V=K/r (K being constant). If the position vector $\to r = 2 ˆ i + 3 ˆ j + 6 ˆ k$ , then the electric field will be
$\frac{2 ˆ i + 3 ˆ j + 6 ˆ k}{243} K$
$\frac{2 ˆ i + 3 ˆ j + 6 ˆ k}{343} K$
$\frac{3 ˆ i + 2 ˆ j + 6 ˆ k}{243} K$
$\frac{3 ˆ i + 2 ˆ j + 6 ˆ k}{343} K$

A

\frac{3 ˆ i + 2 ˆ j + 6 ˆ k}{343} K

B

\frac{2 ˆ i + 3 ˆ j + 6 ˆ k}{243} K

C

\frac{2 ˆ i + 3 ˆ j + 6 ˆ k}{343} K

D

\frac{3 ˆ i + 2 ˆ j + 6 ˆ k}{243} K

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