Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What should be ionization energy of sodium atom in order of $10^{- 19}$ ? (c = 3 $\times$ 10 $^{8}$ ms $^{- 1}$ , h = 6.626 $\times$ 10 $^{- 34}$ J s)

Question

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What should be ionization energy of sodium atom in order of

10^{- 19}

? (c = 3

\times

10

^{8}

ms

^{- 1}

, h = 6.626

\times

10

^{- 34}

J s)

Toppr Admin · Accepted Answer

The correct option is D 8-214-xD7-10-x2212-19J-atomEnergy-hc-x3BB-6-63-xD7-10-x2212-34-xD7-3-xD7-106-joule-0-08219-xD7-10-x2212-17joule-atom-x2234- -8-219-xD7-10-x2212-19j-atom-x2248-8-214-xD7-10-x2212-19j-atom

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. What is the ionization energy of sodium per atom?
$494.5 \times 10^{- 6} J / a t o m$
$3169.5 \times 10^{- 10} J / a t o m$
$5.85 \times 10^{- 15} J / a t o m$
$8.214 \times 10^{- 19} J / a t o m$

The correct option is D $8.214 \times 10^{- 19} J / a t o m$
Energy= $\frac{h c}{λ} = (\frac{6.63 \times 10^{- 34} \times 3 \times 10^{6}}{})$ joule
$= 0.08219 \times 10^{- 17}$ joule/atom
$∴$ $= 8.219 \times 10^{- 19}$ j/atom
$\approx 8.214 \times 10^{- 19}$ j/atom

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. What is the ionization energy of sodium per atom?494.5×10−6J/atom3169.5×10−10J/atom5.85×10−15J/atom8.214×10−19J/atom

The correct option is D 8.214×10−19J/atomEnergy=hcλ=(6.63×10−34×3×106)joule=0.08219×10−17joule/atom∴ =8.219×10−19j/atom≈8.214×10−19j/atom

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. What is the ionization energy of sodium per atom?
$494.5 \times 10^{- 6} J / a t o m$
$3169.5 \times 10^{- 10} J / a t o m$
$5.85 \times 10^{- 15} J / a t o m$
$8.214 \times 10^{- 19} J / a t o m$

The correct option is D $8.214 \times 10^{- 19} J / a t o m$
Energy= $\frac{h c}{λ} = (\frac{6.63 \times 10^{- 34} \times 3 \times 10^{6}}{})$ joule
$= 0.08219 \times 10^{- 17}$ joule/atom
$∴$ $= 8.219 \times 10^{- 19}$ j/atom
$\approx 8.214 \times 10^{- 19}$ j/atom