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Bohr's Model of a Hydrogen Atom

Question

Electron falls from n = 3 to n = 2 in the hydrogen atom. Then energy emitted is:
10.2 eV
12.09 eV
1.9 eV
19 eV

A

19 eV

B

1.9 eV

C

10.2 eV

D

12.09 eV

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Solution

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Bohr's model
$E = 13.6 [\frac{1}{(2)^{2}} - \frac{1}{(3)^{2}}] [E = \frac{- 13.6 Z^{2}}{n^{2}}]$
$= 1.88 e v$

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