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Standard XII
Physics
Matter Waves
Question
Electrons of mass m with de-Broglie wavelength
λ
fall on the target in an X-rays tube. The cutoff wavelength
(
λ
0
)
of the emitted X-rays is
λ
0
=
2
m
c
λ
2
h
λ
0
=
λ
λ
0
=
2
h
m
c
λ
0
=
2
m
2
c
2
λ
3
h
2
A
λ
0
=
λ
B
λ
0
=
2
m
2
c
2
λ
3
h
2
C
λ
0
=
2
m
c
λ
2
h
D
λ
0
=
2
h
m
c
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Solution
Verified by Toppr
Using de-Broglie equation
λ
=
h
p
where
p
=
√
2
m
E
⟹
λ
=
h
√
2
m
E
Energy of the X-ray emitted
E
=
h
c
λ
o
∴
λ
=
h
√
2
m
×
h
c
λ
o
⟹
λ
o
=
2
m
c
λ
2
h
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Similar Questions
Q1
Electrons of mass
m
with de-Broglie wavelength
λ
fall on the target in an X-rays tube. The cutoff wavelength
(
λ
0
)
of the emitted X-rays is