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Energy of a Capacitor

Question

Electrostatic energy of $3.5 \times 10^{- 4} J$ is stored in a capacitor at $700 V$ . What is the charge on the capacitor ?

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Solution

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Given : $u = 3.5 \times 10^{- 4} J$ , $V = 700 V$
$u = \frac{1}{2} Q V$
$Q = \frac{2 u}{V}$
$= \frac{2 \times 3.5 \times 10^{- 4}}{700}$
$Q = 10^{- 6} C$

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