Energy stored in between the plates of parallel plate capacitor of area $A$ , separated by distance $d$ is:
$\frac{1}{2} ε_{0} E^{2} A d$
$\frac{1}{2} ε_{0} E^{2} \frac{A}{d}$
$\frac{1}{2} \frac{A d}{ε_{0} E^{2}}$
$\frac{1}{2} ε_{0} \frac{d}{E^{2} A}$

Question

Energy stored in between the plates of parallel plate capacitor of area $A$ , separated by distance $d$ is:
$\frac{1}{2} ε_{0} E^{2} A d$
$\frac{1}{2} ε_{0} E^{2} \frac{A}{d}$
$\frac{1}{2} \frac{A d}{ε_{0} E^{2}}$
$\frac{1}{2} ε_{0} \frac{d}{E^{2} A}$

Toppr Admin · Accepted Answer

Energy stored in a capacitor of capacitance- E-12CV2Capacitance of parallel plate capacitor -x3F5-0AdPotential difference across parallel plate capacitor due to presence of electric field- V-E-xD7-dThus- energy stored in capacitor -12-x3F5-0Ad-Ed-2-12-x3F5-0E2Ad

Energy stored in between the plates of parallel plate capacitor of area A, separated by distance d is:12ε0E2Ad12ε0E2Ad12Adε0E212ε0dE2A

Energy stored in a capacitor of capacitance: E=12CV2Capacitance of parallel plate capacitor =ϵ0AdPotential difference across parallel plate capacitor due to presence of electric field, V=E×dThus, energy stored in capacitor =12(ϵ0Ad)(Ed)2=12ϵ0E2Ad

Energy stored in between the plates of parallel plate capacitor of area $A$ , separated by distance $d$ is:
$\frac{1}{2} ε_{0} E^{2} A d$
$\frac{1}{2} ε_{0} E^{2} \frac{A}{d}$
$\frac{1}{2} \frac{A d}{ε_{0} E^{2}}$
$\frac{1}{2} ε_{0} \frac{d}{E^{2} A}$