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Question

Eo values for the half cell reactions are given:
Cu2++eCu+; Eo=0.15V
Cu2++2eCu; Eo=0.34V

What will be the Eo of the half-cell: Cu++eCu?

  1. +0.30V
  2. +0.49V
  3. +0.19V
  4. +0.53V

A
+0.53V
B
+0.49V
C
+0.19V
D
+0.30V
Solution
Verified by Toppr

Given,
Cu2++eCu+;E01=0.15V,ΔG01,n1=1

Cu2++2eCu;E02=0.34V,ΔG02,n2=2

Cu++eCu;E03=?V,ΔG03,n3=1

As ΔG is an extensive property,

ΔG03=ΔG02ΔG01

n3FE03=n2FE02+n1FE01

E03=2×0.34+1×0.15

E03=0.680.15=0.53V

Hence, option C is correct.

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Similar Questions
Q1
Eo values for the half cell reactions are given:
Cu2++eCu+; Eo=0.15V
Cu2++2eCu; Eo=0.34V

What will be the Eo of the half-cell: Cu++eCu?

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Q2
Given,
Cu2++2eCu;Eo=0.337V
Cu2++eCu+;Eo=0.153V
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Q3
If for the half-cell reactions
Cu2++eCu+Eo=0.15 V
Cu2++2eCuEo=0.34 V
Calculate Eo of the half cell reaction Cu++eCu
Also predict whether Cu+ undergoes disproportionation or not.
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Q4
If for the half cell reactions Cu2++eCu+ Eo=0.15V
Cu2++2eCu Eo=0.34V
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Q5
Given (i) Cu2++2eCu,Eo=+0.337V

(ii) Cu2++eCu+Eo=+0.153V

Electrode potential, E0 for the reaction will be:
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