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Question

EforCr3++3eCr and Cr3++eCr2+ are 0.74V and 0.40V, respectively. E for the reaction is: Cr+2+2eCr
  1. 0.91V
  2. +0.91V
  3. -1.14V
  4. +0.34V

A
-1.14V
B
0.91V
C
+0.91V
D
+0.34V
Solution
Verified by Toppr

Cr3++3eCr;
Cr3++eCr2+;
Cr2++2eCr;
E3=n1E1n2E2n3
=[3×(0.74)][(1)×(40)]2=0.91V

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EforCr3++3eCr and Cr3++eCr2+ are 0.74V and 0.40V, respectively. E for the reaction is: Cr+2+2eCr
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