Equal masses of S-2- S-4 and S-8 are taken- Highest number of species are present in-S-2S-4all have same number of moleculeS-8

Question

Toppr Admin · Accepted Answer

The order of molecular weights will beS2-lt-S4-lt-S8-So- if the the equal masses are taken- then highest number of molecules will be in S2-So- correct answer is option A-

Equal masses of $S_{2}, S_{4}$ and $S_{8}$ are taken. Highest number of free species are present in:
$S_{2}$
$S_{4}$
all have same number of molecule
$S_{8}$

The order of molecular weights will be
$S_{2} < S_{4} < S_{8}$ .
So, if the the equal masses are taken, then highest number of molecules will be in $S_{2}$ .
So, correct answer is option A.

Equal masses of S2,S4 and S8 are taken. Highest number of free species are present in:S2S4all have same number of moleculeS8

The order of molecular weights will beS2<S4<S8.So, if the the equal masses are taken, then highest number of molecules will be in S2.So, correct answer is option A.

Equal masses of $S_{2}, S_{4}$ and $S_{8}$ are taken. Highest number of free species are present in:
$S_{2}$
$S_{4}$
all have same number of molecule
$S_{8}$

The order of molecular weights will be
$S_{2} < S_{4} < S_{8}$ .
So, if the the equal masses are taken, then highest number of molecules will be in $S_{2}$ .
So, correct answer is option A.