Question

Equation of oblique projectile can be written as:

• A. $y=xsin\theta (1-\frac{x}{R})$
• B. $y=xtan\theta (1-\frac{x}{R})$
• C. $y=xtan\theta (1-\frac{x}{T})$
• D. $y=xtan\theta (1-\frac{x}{H})$

Answer 1

Answer: (B)

The correct option is B $y=xtan\theta (1-\frac{x}{R})$
The equation of an oblique projectile is given by:

$y=x\tan \theta -\frac{g{x}^2}{2u^2{\cos }^2\theta }$

$y=x\tan \theta -\frac{x^2}{\left(2u^2{\cos }^2\theta /g\right)}$

$y=x\tan \theta -\frac{x^2\sin \theta }{\cos \theta \left(2u^2\sin \theta \cos \theta \right)/g}$

$y=x\tan \theta -\frac{x^2\sin \theta }{\cos \theta \left(u^2\sin 2\theta /g\right)}$

$y=x\tan \theta -\frac{x^2\tan \theta }{R}$

$y=x\tan \theta (1-\frac{x}{R})$