Question

Equipotential surfaces are shown in fig, then the electric field strength will be
1224828_1fdfa6cbc47c432ab0320203eec5d923.png

A
100 Vm-1 along X-axis
B
100 Vm-1 along Y-axis
C
200 Vm-1 at an angle 1200 wirh X-axis
D
50 Vm-1 at an angle 1800 wirh X-axis
Solution
Verified by Toppr

Using, dV=Edr
ΔV=EΔrcsθ
E=ΔVΔrcosθ
E=(2010)10×102cos1200=1010×102(sin300)=1021/2=200V/m
direction of E be perpendicular to the equipotential surface i.e., at 1200 with x axis.
Hence,
option (C) is correct answer.

Was this answer helpful?
6
Similar Questions
Q1

The electric potential at a point is given by V=6x2 The electric field strength at x=2 is


View Solution
Q2

The compressibility factor of a gas is less than 1 at STP. Its molar volume Vm will be:


View Solution
Q3

Initially a man and a plank of the same mass m are moving on smooth horizontal surface with a velocity v m/s along positive x-axis. After some time man jumps along negative x-axis with a velocity v m/s with respect to ground, then the speed of the plank will be

View Solution
Q4

Figure shows equipotential concentric surfaces centred at O. The magnitude of electric field at a distance r measured from O is:


View Solution
Q5

A plane electromagnetic wave travels in free space along the x-direction. The electric field component of the wave at a particular point of space and time is E=6 Vm1 along y-direction. Its corresponding magnetic field component, B would be

View Solution
Solve
Guides