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The equivalent resistance of $R_{1}$ and $R_{2}$ in parallel is,

$R_{eq}1 =R_{1}1 +R_{2}1 $

$⟹R_{eq}=R_{1}+R_{2}R_{1}R_{2} $

For any values of $R_{1}$ and $R_{2}$, $R_{eq}$ will be less than $R_{1}$ and $R_{2}$.

For example,

Let $R_{1}=2Ω$

$R_{2}=6Ω$

Then,

Equivalent resistance of $R_{1}$ and $R_{2}$ in parallel,

$R_{eq}=R_{1}+R_{2}R_{1}R_{2} $

$R_{eq}=2+82×6 $

$R_{eq}=812 $

$R_{eq}=1.5Ω$

$⟹R_{eq}<R_{1}andR_{eq}<R_{2}$

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