Escape velocity at earth's surface is 11.2km/s. Escape velocity at the surface of a planet having mass 100 times and radius 4 times that of earth will be

56km/s

112km/s

305km/s

11.2km/s

A

112km/s

B

305km/s

C

56km/s

D

11.2km/s

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Solution

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Ve=√2gR

Ve=√2GMR[∴g=GMR2]

Now,

11.1Km/hr=√2GMR

V1e=√2G(100M)4R

11.1V1e=15

V1e=55.5 Km/hr

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