Escape velocity from earth is 11-2 km-sec- Another planet of same mass has radius dfrac -1-4- times that of earth- What is the escape velocity from this planet -11-2 km-sec22-4 km-sec44-8 km-sec5-6 km-sec

Question

Toppr Admin · Accepted Answer

Escape velocity - -xA0-ve-x221A-2GMeRe-11-2km-sFor R-x2032-Re4M-x2032-Mev-x2032-e-xE001-xE000-xE000-xE000-x23B7-2GMeRe4-2ve-22-4km-s

Escape velocity from earth is $11.2 k m / s e c$ . Another planet of same mass has radius $\frac{1}{4}$ times that of earth. What is the escape velocity from this planet ?
$11.2 k m / s e c$
$22.4 k m / s e c$
$44.8 k m / s e c$
$5.6 k m / s e c$

Escape velocity , $v_{e} = \sqrt{\frac{2 G M_{e}}{R_{e}}} = 11.2 k m / s$
For $R^{'} = \frac{R_{e}}{4} M^{'} = M_{e}$

$v_{e}^{'} = \sqrt{\frac{2 G M_{e}}{\frac{R_{e}}{4}}} = 2 v_{e} = 22.4 k m / s$

Escape velocity from earth is 11.2km/sec. Another planet of same mass has radius 14 times that of earth. What is the escape velocity from this planet ?11.2km/sec22.4km/sec44.8km/sec5.6km/sec

Escape velocity , ve=√2GMeRe=11.2km/sFor R′=Re4M′=Mev′e=  ⎷2GMeRe4=2ve=22.4km/s

Escape velocity from earth is $11.2 k m / s e c$ . Another planet of same mass has radius $\frac{1}{4}$ times that of earth. What is the escape velocity from this planet ?
$11.2 k m / s e c$
$22.4 k m / s e c$
$44.8 k m / s e c$
$5.6 k m / s e c$

Escape velocity , $v_{e} = \sqrt{\frac{2 G M_{e}}{R_{e}}} = 11.2 k m / s$
For $R^{'} = \frac{R_{e}}{4} M^{'} = M_{e}$

$v_{e}^{'} = \sqrt{\frac{2 G M_{e}}{\frac{R_{e}}{4}}} = 2 v_{e} = 22.4 k m / s$