Ethyl ether when reacted with chlorine in dark yields
Question 27 The heteroatoms present in CH3βCH2βOβCH2βCH2Cl are ββββββ (i) oxygen (ii) carbon (iii) hydrogen (iv) chlorine (a) (i) and (ii) (b) (ii) and (iii) (c) (iii) and (iv) (d) (i) and (iv)
Complete the following reaction: H2C=CHβCH3+HClβ
CH3βCCH+HClβ
Which are free radical reactions
I.CH3βCH=CH2+HBrPeroxideββββββCH3βCH2βCH2BrII.CH3βCH=CH2+HBrβCH3βCHBrβCH3III.CH3βCH=CH2+Cl2βClCH2βCH=CH2IV.CH3βCH3+Cl2βClCH2βCH3
The IUPAC name of the compound CH3βCH(CH3)βCH2βCH2Cl is: