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Standard XII
Mathematics
Question
Evaluate
103
3
.
1092727
1398477
1847267
1106327
A
1398477
B
1092727
C
1847267
D
1106327
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Solution
Verified by Toppr
(
100
+
3
)
3
Using
(
a
+
b
)
3
=
a
3
+
b
3
+
3
a
b
(
a
+
b
)
=
(
100
)
3
+
(
3
)
3
+
3
(
100
)
(
3
)
(
100
+
3
)
=
1000000
+
27
+
900
(
100
+
3
)
=
1000000
+
27
+
90000
+
2700
=
1092727
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