Evaluate -a-b-a-b-b-c-b-c-c-a-c-a-

Question

Toppr Admin · Accepted Answer

We are given-a-b-a-x2212-b-b-c-b-x2212-c-c-a-c-x2212-a-a2b2-b2-x2212-c2-c2-x2212-a2-a2-x2212-a2-b2-x2212-b2-c2-x2212-c2-0So- -a-b-a-x2212-b-b-c-b-x2212-c-c-z-c-x2212-a-

Evaluate $(a + b) (a - b) + (b + c) (b - c) + (c + a) (c - a)$ .

We are given,
$(a + b) (a - b) + (b + c) (b - c) + (c + a) (c - a)$
$= (a^{2} b^{2}) + (b^{2} - c^{2}) + (c^{2} - a^{2})$
$= (a^{2} - a^{2}) + (b^{2} - b^{2}) + (c^{2} - c^{2})$
$= 0$
So, $(a + b) (a - b) + (b + c) (b - c) + (c + z) (c - a)$

Evaluate (a+b)(a−b)+(b+c)(b−c)+(c+a)(c−a).

We are given,(a+b)(a−b)+(b+c)(b−c)+(c+a)(c−a)=(a2b2)+(b2−c2)+(c2−a2)=(a2−a2)+(b2−b2)+(c2−c2)=0So, (a+b)(a−b)+(b+c)(b−c)+(c+z)(c−a)

Evaluate $(a + b) (a - b) + (b + c) (b - c) + (c + a) (c - a)$ .

We are given,
$(a + b) (a - b) + (b + c) (b - c) + (c + a) (c - a)$
$= (a^{2} b^{2}) + (b^{2} - c^{2}) + (c^{2} - a^{2})$
$= (a^{2} - a^{2}) + (b^{2} - b^{2}) + (c^{2} - c^{2})$
$= 0$
So, $(a + b) (a - b) + (b + c) (b - c) + (c + z) (c - a)$