Evaluate - dfrac-3-8- - dfrac-5-12-

Question

Toppr Admin · Accepted Answer

- -dfrac-3-8- - -dfrac-5-12- -Here LCM of -8- and -12 - is -24 -160-So we get-160- - -dfrac-3 -times 3-8 -times 3- - -dfrac-5 -times 2-12 -times 2- -160-By further calculation-160- - -dfrac-9 - 10-24- -160- - -dfrac-19-24- -160-

Evaluate :
$$ \dfrac{-3}{8} + \dfrac{-5}{12} $$

$$ \dfrac{-3}{8} + \dfrac{-5}{12} $$
Here LCM of $$8$$ and $$12 $$ is $$24 $$
So we get
$$ = \dfrac{-3 \times 3}{8 \times 3} + \dfrac{-5 \times 2}{12 \times 2} $$
By further calculation
$$ = \dfrac{-9 - 10}{24} $$
$$ = \dfrac{-19}{24} $$

Evaluate :$$ \dfrac{-3}{8} + \dfrac{-5}{12} $$

$$ \dfrac{-3}{8} + \dfrac{-5}{12} $$Here LCM of $$8$$ and $$12 $$ is $$24 $$ So we get $$ = \dfrac{-3 \times 3}{8 \times 3} + \dfrac{-5 \times 2}{12 \times 2} $$ By further calculation $$ = \dfrac{-9 - 10}{24} $$ $$ = \dfrac{-19}{24} $$

Evaluate :
$$ \dfrac{-3}{8} + \dfrac{-5}{12} $$

$$ \dfrac{-3}{8} + \dfrac{-5}{12} $$
Here LCM of $$8$$ and $$12 $$ is $$24 $$
So we get
$$ = \dfrac{-3 \times 3}{8 \times 3} + \dfrac{-5 \times 2}{12 \times 2} $$
By further calculation
$$ = \dfrac{-9 - 10}{24} $$
$$ = \dfrac{-19}{24} $$