Evaluate - dfrac-4-9- - dfrac-2-3-

Question

Toppr Admin · Accepted Answer

- -dfrac-4-9- - -dfrac-2-3- -Taking LCM-3- 9-3-5- 3-1-1-1-8756-LCM of 3 and 9-9- -dfrac-4-9- - -dfrac-2-3- - -dfrac-4 -times 1-9 -times1- - -dfrac-left - -2 -times3 -right -3 -times 3- - -dfrac-4 - 6-9- - -dfrac-2-9-160-

Evaluate :
$$ \dfrac{-4}{9} - \dfrac{2}{-3} $$

$$ \dfrac{-4}{9} - \dfrac{2}{-3} $$
Taking LCM
$$3| 9,3$$
$$5| 3,1$$
$$|1,1$$
(∴LCM of 3 and 9=9)
$$ \dfrac{-4}{9} - \dfrac{2}{-3} = \dfrac{-4 \times 1}{9 \times1} - \dfrac{\left ( -2 \times3 \right )}{3 \times 3}$$
$$ = \dfrac{-4 + 6}{9} = \dfrac{2}{9}$$

Evaluate :$$ \dfrac{-4}{9} - \dfrac{2}{-3} $$

$$ \dfrac{-4}{9} - \dfrac{2}{-3} $$Taking LCM$$3| 9,3$$$$5| 3,1$$$$|1,1$$(∴LCM of 3 and 9=9)$$ \dfrac{-4}{9} - \dfrac{2}{-3} = \dfrac{-4 \times 1}{9 \times1} - \dfrac{\left ( -2 \times3 \right )}{3 \times 3}$$$$ = \dfrac{-4 + 6}{9} = \dfrac{2}{9}$$

Evaluate :
$$ \dfrac{-4}{9} - \dfrac{2}{-3} $$

$$ \dfrac{-4}{9} - \dfrac{2}{-3} $$
Taking LCM
$$3| 9,3$$
$$5| 3,1$$
$$|1,1$$
(∴LCM of 3 and 9=9)
$$ \dfrac{-4}{9} - \dfrac{2}{-3} = \dfrac{-4 \times 1}{9 \times1} - \dfrac{\left ( -2 \times3 \right )}{3 \times 3}$$
$$ = \dfrac{-4 + 6}{9} = \dfrac{2}{9}$$