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Question

Evaluate :
$$ \dfrac{-8}{9} \times \dfrac{-3}{16} $$

Solution
Verified by Toppr

$$ \dfrac{-8}{9} \times \dfrac{-3}{16} $$
It can be written as
$$ = \dfrac{-8 \times -3}{9 \times 16} $$
By further calculation
$$ = \dfrac{-1 \times -1}{3 \times 2} $$
$$ = \dfrac{1}{6} $$

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