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Question

Evaluate the following, using the distributive property.
(i)39×99
(ii) (85)×43+43×(15)
(iii) 53×(9)(109)×53
(iv) 68×(17)+(68)×3

Solution
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Distributive property is a×(b+c)=a×b+a×c
Associative property is a×b±a×c=a×(b±c)
using this in given examples.

(i)
39×99=39×[1001]
=39×100(39)×1[distributive property]=3900+39=3861

(ii)
(85)×43+43×(15)
=43×(85)+43×(15)[a×b=b×a]
=43×[8515][associative property]
=43×(100)=4300

(iii)
53×(9)(109)×53
53×(9)53×(109)[a×b=b×a]
=53×[(9)(109)][associative property]
=53×[9+109]=53×100=5300

(iv)
68×(17)+(68)×3=68×(17)68×3
=68×[(17)3][associative property]
=68×(20)
=1360

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Similar Questions
Q1
Evaluate the following, using the distributive property.
(i)39×99
(ii) (85)×43+43×(15)
(iii) 53×(9)(109)×53
(iv) 68×(17)+(68)×3
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Q2

Question 124 (iii)

Evaluate the following, using distributive property.
53×(9)(109)×53

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Q3

Question 124 (iv)

Evaluate the following, using distributive property.
68×(17)+(68)×3

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Evaluate the following, using distributive property.
(85)×43+43×(15)

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Use property to evaluate :

935343

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