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Standard XII
Mathematics
Integration Using Substitution
Question
Evaluate the integrals
∫
2
0
1
(
x
2
+
1
)
d
x
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Solution
Verified by Toppr
Let
x
=
t
a
n
θ
⇒
d
x
=
s
e
c
2
θ
d
θ
⇒
∫
2
0
1
s
e
c
2
θ
s
e
c
2
θ
d
θ
⇒
∫
2
0
θ
=
∫
2
0
t
a
n
−
1
x
⇒
t
a
n
−
1
2
−
0
=
t
a
n
−
1
2
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