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Standard VIII
Mathematics
Algebraic Identities
Question
Evaluate the value of
(
101
)
2
by using suitable identity
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Solution
Verified by Toppr
(
101
)
2
=
(
100
+
1
)
2
Using
(
a
+
b
)
2
=
a
2
+
b
2
+
2
a
b
(
100
+
1
)
2
=
100
2
+
1
2
+
2
×
100
×
1
=
10000
+
1
+
200
=
10000
+
201
=
10201
.
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