0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Example 4 Construct \( \angle A O B = 60 ^ { \circ } . \) Mark a point P equidistant from OA and \( O B \) such that its distance from another given line \( C D \) is 2\( \cdot 5 \mathrm { cm } \)

Solution
Verified by Toppr


Was this answer helpful?
4
Similar Questions
Q1
Draw a line segment $$OA = 5 \,cm.$$ Use set-square to construct angle $$AOB = 60^\circ,$$ such that $$OB = 3 \,cm.$$ Join A and B; then measure the length of AB.
View Solution
Q2
Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of ĀÆĀÆĀÆĀÆĀÆĀÆĀÆĀÆOA and ĀÆĀÆĀÆĀÆĀÆĀÆĀÆĀÆOB. Let them meet at P. Is PA = PB?
[4 mark]
View Solution
Q3

Use ruler and compasses only for the following question. All construction lines and arcs must be clearly shown.

(i) Construct a āˆ†ABCin which BC=6.5cmāˆ ABC=60āˆ˜,AB=5cm.

(ii) construct the locus of points equidistant of 3.5cmfrom A.

(iii) construct the locus of points equidistant from AC and BC.

(iv) mark 2points X and Y which are at a distance of 3.5cm from A and also equidistant from AC and BC measure XY.


View Solution
Q4

P is a point on a circle with center O. If P is equidistant from the two radii OA and OB, prove that arc AP= arc BP.


View Solution
Q5

Draw any angle āˆ AOB, such that OA=OB=6cm. Construct perpendicular bisectors of OA and OB. Let them meet at P. Is PA=PB? Verify this by actual measurement.


View Solution