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Example \( 6 : \) In Fig. 5.31 \( \mathrm { OA } \cdot \mathrm { OB } = \mathrm { OC } \cdot \mathrm { OD } \) Show that \( \angle A = \angle C \) and \( \angle B = \angle D \) Solution: \( \mathrm { OA } . \mathrm { OB } = \mathrm { OC } . \) OD \( \mathrm { OA } _ { - } \mathrm { OD } \)

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