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Standard XI
Mathematics
NCERT
Question
Expand
(
x
+
1
x
)
6
Open in App
Solution
Verified by Toppr
(
x
+
1
x
)
6
=
6
C
+
0
(
x
)
6
+
C
1
(
x
)
5
(
1
x
)
+
6
C
2
(
x
)
4
(
1
x
)
2
+
6
C
3
(
x
)
3
(
1
x
)
3
+
6
C
4
(
x
)
2
(
1
x
)
4
+
6
C
5
(
x
)
(
1
x
)
5
+
6
C
6
(
1
x
)
6
=
x
6
+
6
(
x
)
5
(
1
x
)
+
15
(
x
)
4
(
1
x
2
)
+
20
(
x
)
3
(
1
x
3
)
+
15
(
x
)
2
(
1
x
4
)
+
6
(
x
)
(
1
x
5
)
+
1
x
6
=
x
6
+
6
x
4
+
15
x
2
+
20
+
15
x
2
+
6
x
4
+
1
x
6
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