$ f ( x ) = \sqrt [ 3 ] { x } $

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Which of the following transformations in order will give $- | (- x) + 3 |$ from $| x |$ ?
(1) $f (x) \to f (- x)$
(2) $f (x) \to f (x + 3)$
(3) $f (x) \to - f (x)$

(4) $f (x) \to f (x - 3)$

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Find

\lim_{x \to 3} f (x)

, where

f (x) = \{\begin{cases} 4, & if x > 3 \\ x + 1, & if x < 3 \end{cases}

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Find

\lim_{x \to 3} f (x)

, where

f (x) = \{\begin{cases} 4, & if x \geq 3 \\ x + 1, & if x < 3 \end{cases}

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f (x + \frac{1}{2}) + f (x - \frac{1}{2}) = f (x)

\forall x \in R,

then

f (x - 3) + f (x + 3)

is equal to

View Solution

Which of the following transformations in order will give $- | (- x) + 3 |$ from $| x |$ ?
(1) $f (x) \to f (- x)$
(2) $f (x) \to f (x + 3)$
(3) $f (x) \to - f (x)$

(4) $f (x) \to f (x - 3)$

View Solution

\( f ( x ) = \sqrt [ 3 ] { x } \)