(2x−32x3)=?(a) 2(x−4)(x+4)(b) 2x(1−2x)2(c) 2x(1+2x)2(d) 2x(1−4x)(1+4x)
Solve for x:tan−1(x−1)+tan−1x+tan−1(x+1)=tan−13x.
OR
Prove that : (6x−8x31−12x2)−tan−1(4x1−4x2)=tan−12x;|2x|<1√3.