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Question

Factorise:
16(2p3q)24(2p3q)
  1. (2p3q)(8p12q1)
  2. 4(2p3q)(8pq1)
  3. (2p3q)(8pq1)
  4. 4(2p3q)(8p12q1)

A
4(2p3q)(8pq1)
B
(2p3q)(8p12q1)
C
(2p3q)(8pq1)
D
4(2p3q)(8p12q1)
Solution
Verified by Toppr

16(2p3q)24(2p3q)
=4(2p3q)[4(2p3q)1] take 4(2p-3q) common,
=4(2p3q)(8p12q1)

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