Factorize-25-2a - b-2- - 81b-2-4-5a - 2b- -5a - 7b-3-5a - 2b- -5a - 7b-5-5a - 2b- -5a - 7b-5a - 2b- -5a - 7b-

Question

Toppr Admin · Accepted Answer

-xA0- -xA0- 25-2a-x2212-b-2-x2212-81b2-10a-x2212-5b-2-x2212-9b-2Using -a2-x2212-b2-a-b-a-x2212-b- we get-10a-x2212-5b-9b-10a-x2212-5b-x2212-9b-10a-4b-10a-x2212-14b-4-5a-2b-5a-x2212-7b-

Factorize:
$25 (2 a - b)^{2} - 81 b^{2}$ .
$4 (5 a + 2 b) (5 a - 7 b)$
$3 (5 a + 2 b) (5 a - 7 b)$
$5 (5 a + 2 b) (5 a - 7 b)$
$(5 a + 2 b) (5 a - 7 b)$

$25 (2 a - b)^{2} - 81 b^{2}$
$= (10 a - 5 b)^{2} - (9 b)^{2}$
Using [ $a^{2} - b^{2} = (a + b) (a - b)$ ], we get
$= (10 a - 5 b + 9 b) (10 a - 5 b - 9 b)$
$= (10 a + 4 b) (10 a - 14 b)$
$= 4 (5 a + 2 b) (5 a - 7 b)$

Factorize:25(2a−b)2−81b2.4(5a+2b)(5a−7b)3(5a+2b)(5a−7b)5(5a+2b)(5a−7b)(5a+2b)(5a−7b)

25(2a−b)2−81b2=(10a−5b)2−(9b)2Using [a2−b2=(a+b)(a−b)], we get=(10a−5b+9b)(10a−5b−9b)=(10a+4b)(10a−14b)=4(5a+2b)(5a−7b)

Factorize:
$25 (2 a - b)^{2} - 81 b^{2}$ .
$4 (5 a + 2 b) (5 a - 7 b)$
$3 (5 a + 2 b) (5 a - 7 b)$
$5 (5 a + 2 b) (5 a - 7 b)$
$(5 a + 2 b) (5 a - 7 b)$

$25 (2 a - b)^{2} - 81 b^{2}$
$= (10 a - 5 b)^{2} - (9 b)^{2}$
Using [ $a^{2} - b^{2} = (a + b) (a - b)$ ], we get
$= (10 a - 5 b + 9 b) (10 a - 5 b - 9 b)$
$= (10 a + 4 b) (10 a - 14 b)$
$= 4 (5 a + 2 b) (5 a - 7 b)$