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Standard IX
Mathematics
Question
Factorize:
a
2
−
(
2
a
+
3
b
)
2
.
−
3
(
a
+
b
)
(
a
+
3
b
)
3
(
a
+
b
)
(
a
+
3
b
)
−
3
(
a
−
b
)
(
a
−
3
b
)
3
(
a
+
b
)
(
a
−
3
b
)
A
−
3
(
a
+
b
)
(
a
+
3
b
)
B
3
(
a
+
b
)
(
a
−
3
b
)
C
3
(
a
+
b
)
(
a
+
3
b
)
D
−
3
(
a
−
b
)
(
a
−
3
b
)
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Solution
Verified by Toppr
a
2
−
(
2
a
+
3
b
)
2
=
(
a
+
2
a
+
3
b
)
(
a
−
2
a
−
3
b
)
=
(
3
a
+
3
b
)
(
−
a
−
3
b
)
=
−
3
(
a
+
b
)
(
a
+
3
b
)
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Similar Questions
Q1
Factorise :
2
a
+
6
b
−
3
(
a
+
3
b
)
2
2
a
+
6
b
−
3
(
a
+
3
b
)
2
=
2
(
a
+
3
b
)
−
3
(
a
+
3
b
)
2
[
T
a
k
i
n
g
2
c
o
m
m
o
n
f
r
o
m
2
a
+
6
b
]
=
(
a
+
3
b
)
{
2
−
3
(
a
+
3
b
)
}
[
T
a
k
i
n
g
(
a
+
3
b
)
c
o
m
m
o
n
]
=
(
a
+
3
b
)
(
2
−
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a
−
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View Solution
Q2
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
2
a
3
a
+
2
b
4
a
+
3
b
+
2
c
3
a
6
a
+
3
b
10
a
+
6
b
+
3
a
∣
∣ ∣
∣
=
a
3
View Solution
Q3
What should be added to 4a to get 7a - 3b + 3?
View Solution
Q4
3
a
−
[
4
a
−
¯
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
¯
3
a
−
5
b
−
3
{
2
a
−
(
3
a
−
¯
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
¯
2
a
−
3
b
)
}
]
equals
View Solution
Q5
Simplify:
2
a
−
[
3
b
−
{
a
−
(
2
c
−
3
b
)
+
4
c
−
3
(
a
−
b
−
2
c
)
}
]
View Solution