Let the age of two children be $$ \mathrm{x} $$ and $$ \mathrm{y} $$
So, the father's present age $$ =3(x+y) $$
After five years, Age of two children $$ =(x+5)+(y+5) $$ years $$ =(x+y+10) $$ years
So, the age of father after five years $$ =3(x+y)+5=3 x+3 y+5 $$
According to the question, $$ 3 x+3 y+5=2(x+y+10) $$
$$ \Rightarrow 3 x+3 y+5=2 x+2 y+20 $$
$$ \Rightarrow 3 x-2 x+3 y-2 y=20-5 $$
$$ \Rightarrow \mathrm{x}+\mathrm{y}=15 $$
So, the age of two children $$ =15 $$ years
And the age of father $$ =3(15)=45 $$ years
Hence, the age of father is $$45$$ years and the age of his two children is $$15$$ years.