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So, the father's present age $=3(x+y)$

After five years, Age of two children $=(x+5)+(y+5)$ years $=(x+y+10)$ years

So, the age of father after five years $=3(x+y)+5=3x+3y+5$

According to the question, $3x+3y+5=2(x+y+10)$

$⇒3x+3y+5=2x+2y+20$

$⇒3x−2x+3y−2y=20−5$

$⇒x+y=15$

So, the age of two children $=15$ years

And the age of father $=3(15)=45$ years

Hence, the age of father is $45$ years and the age of his two children is $15$ years.

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