Figure given shows two identical parallel plate capacitors connected to a battery with switch S closed. The switch is now opened and the free space between the plate of capacitors is filled with a dielectric of dielectric constant 2. What will be the ratio of total electrostatic energy stored in both capacitors before and after the introduction of the dielectric?
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Correct option is C)
When switch (S) is closed, U1=21CV2+21CV2=CV2 Charge on B,Q=CV When switch(S) is open and dielectric(K=2) is inserted in both capacitors, potential of A remains same while charge on B remains same. U1=21⋅2C⋅V2+2⋅2CQ2 =CV2+4CC2V2 =45CV2 U2U1=54.
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