Figure shows a closed surface which intersects a conducting sphere. If a positive charge is placed at point P, find the sign of flux passing through the curved surface S.

Question

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Answer 1

By induction the charge induced on the left side of sphere is positive as shown in figure. Thus, the charge enclosed by closed surface S is positive. By Gauss's law the flux is proportional to enclosed charge. Hence the sign of the flux will be positive.

Answer 2

By induction the charge induced on the left side of sphere is positive as shown in figure. Thus, the charge enclosed by closed surface S is positive. By Gauss's law the flux is proportional to enclosed charge. Hence the sign of the flux will be positive.

Figure shows a closed surface which intersects a conducting sphere. If a positive charge is placed at point P, find the sign of flux passing through the curved surface S.

By induction the charge induced on the left side of sphere is positive as shown in figure. Thus, the charge enclosed by closed surface S is positive. By Gauss's law the flux is proportional to enclosed charge. Hence the sign of the flux will be positive.

For a charged conductor at the surface,

lf the electric flux entering and leaving an enclosed surface respectively is $ϕ_{1}$ and $ϕ_{2}$ , the electric charge inside the surface will be :

A hemispherical body is placed in a uniform electric field E. What is the flux linked with the curved surface if the field is perpendicular to the curved surface at every points as in figure.

In space two point charges are placed as shown in figure. The electric field line at point P may be in direction :

A solid non conducting sphere is charged in such a way that in it as we move away from the centre, the electric field decreases then which of the following statement is/are correct :

Revise with Concepts

Area Vector, Solid Angle and Electric Flux

Figure shows a closed surface which intersects a conducting sphere. If a positive charge is placed at point P, find the sign of flux passing through the curved surface S.

By induction the charge induced on the left side of sphere is positive as shown in figure. Thus, the charge enclosed by closed surface S is positive. By Gauss's law the flux is proportional to enclosed charge. Hence the sign of the flux will be positive.

For a charged conductor at the surface,

lf the electric flux entering and leaving an enclosed surface respectively is ϕ1​ and ϕ2​, the electric charge inside the surface will be :

A hemispherical body is placed in a uniform electric field E. What is the flux linked with the curved surface if the field is perpendicular to the curved surface at every points as in figure.

In space two point charges are placed as shown in figure. The electric field line at point P may be in direction :

A solid non conducting sphere is charged in such a way that in it as we move away from the centre, the electric field decreases then which of the following statement is/are correct :

Revise with Concepts

Area Vector, Solid Angle and Electric Flux

lf the electric flux entering and leaving an enclosed surface respectively is $ϕ_{1}$ and $ϕ_{2}$ , the electric charge inside the surface will be :