Solve

Guides

0

Question

Open in App

Solution

Verified by Toppr

In this problem, the work done is $$W = Fd$$, where F is the tension in the cord and d is the length of the cord pulled as the cart slides from $$x_1 $$ to $$x_2$$.

From the figure, we have

$$d = \sqrt{x_1^2 + h^2} - \sqrt{x_2^2 + h^2}$$

$$ = \sqrt{(3.00m)^2 + (1.20 m)^2} - \sqrt{(1.00 m)^2 + (1.20 m)^2} $$

$$= 3.23 m - 1.56 m = 1.67 m$$

which yields $$\Delta K = Fd = (25.0 N)(1.67 m) = 41.7 J.$$

Was this answer helpful?

4