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Question

Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that :
195215_a201816f37464199a78e05c99f0cb564.png
  1. EA>EB>EC
  2. EA=EB=EC
  3. EA=EC>EB
  4. EA=EC<EB

A
EA>EB>EC
B
EA=EC>EB
C
EA=EB=EC
D
EA=EC<EB
Solution
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  • The magnitude of Electric field is proportional to the density of electric field lines
  • Here density of electric field lines at A and C is same. So the electric filed at A and C will be the same. i,e EA=EC
  • E.F. Line density at A and C is greater as compare to line density at B so EA=EC>EB
Hence , option C is correct.

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