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Standard XII
Physics
Question
Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that :
E
A
>
E
B
>
E
C
E
A
=
E
B
=
E
C
E
A
=
E
C
>
E
B
E
A
=
E
C
<
E
B
A
E
A
>
E
B
>
E
C
B
E
A
=
E
C
>
E
B
C
E
A
=
E
B
=
E
C
D
E
A
=
E
C
<
E
B
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Solution
Verified by Toppr
The magnitude of Electric field is proportional to the density of electric field lines
Here density of electric field lines at A and C is same. So the electric filed at A and C will be the same. i,e
E
A
=
E
C
E.F. Line density at A and C is greater as compare to line density at B so
E
A
=
E
C
>
E
B
Hence , option C is correct.
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Similar Questions
Q1
Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that
(a) E
A
> E
B
> E
C
(b) E
A
= E
B
= E
C
(c) E
A
= E
C
> E
B
(d) E
A
= E
C
< E
B