Figure shows the field produced by two point charges +q and -q of equal magnitude but opposite signs (an electric dipole). Find the electric flux through each of the closed surfaces A, B, C and D.

Question

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Answer 1

Flux through closed surface A, $ϕ_{A} = \frac{Q _{i n}}{ϵ _{0}} = \frac{q}{ϵ _{0}}$
Flux through closed surface B, $ϕ_{B} = \frac{Q _{i n}}{ϵ _{0}} = - \frac{q}{ϵ _{0}}$
Flux through closed surface C, $ϕ_{C} = \frac{Q _{i n}}{ϵ _{0}} = \frac{q - q}{ϵ _{0}} = 0$
Flux through closed surface D, $ϕ_{D} = \frac{Q _{i n}}{ϵ _{0}} = 0$

Answer 2

Flux through closed surface A,

ϕ_{A} = \frac{Q _{i n}}{ϵ _{0}} = \frac{q}{ϵ _{0}}

Flux through closed surface B,

ϕ_{B} = \frac{Q _{i n}}{ϵ _{0}} = - \frac{q}{ϵ _{0}}

Flux through closed surface C,

ϕ_{C} = \frac{Q _{i n}}{ϵ _{0}} = \frac{q - q}{ϵ _{0}} = 0

Flux through closed surface D,

ϕ_{D} = \frac{Q _{i n}}{ϵ _{0}} = 0