Figure shows three points A- B and C in a region of uniform electric field -E- The line AB is perpendicular and BC is parallel to the field lines- Then which of the following holds good- Here VA-VB and VC represents the electric potential point A- B and C respectively-

Question

Toppr Admin · Accepted Answer

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface- So- VA-VB and VB-gt-VC

Figure shows three points A, B and C in a region of uniform electric field $\to E$ . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Here $V_{A}, V_{B}$ and $V_{C}$ represents the electric potential at point A, B and C respectively.

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface. So, $V_{A} = V_{B}$ and $V_{B} > V_{C}$

Figure shows three points A, B and C in a region of uniform electric field →E. The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Here VA,VB and VC represents the electric potential at point A, B and C respectively.

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface. So, VA=VB and VB>VC

Figure shows three points A, B and C in a region of uniform electric field $\to E$ . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Here $V_{A}, V_{B}$ and $V_{C}$ represents the electric potential at point A, B and C respectively.

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface. So, $V_{A} = V_{B}$ and $V_{B} > V_{C}$