Figure shows three points A, B and C in a region of uniform electric field $E$ . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Here $V_{A}, V_{B}$ and $V_{C}$ represents the electric potential at point A, B and C respectively.

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Answer 1

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface. So, $V_{A} = V_{B}$ and $V_{B} > V_{C}$

Answer 2

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface. So,

V_{A} = V_{B}

and

V_{B} > V_{C}

Figure shows three points A, B and C in a region of uniform electric field $E$ . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Here $V_{A}, V_{B}$ and $V_{C}$ represents the electric potential at point A, B and C respectively.

$V_{A} = V_{B} = V_{C}$

$V_{A} = V_{B} > V_{C}$

$V_{A} = V_{B} < V_{C}$

$V_{A} > V_{B} = V_{C}$

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface. So, $V_{A} = V_{B}$ and $V_{B} > V_{C}$

A, B and C are three points in a uniform electric field. The electric potential is :

$V_{0}$ is the potential at the origin in an electric field. $E = E_{x} i - E_{y} j$ . The potential at the point (x,y) is:

Figure shows three spherical and equipotential surfaces $A$ , $B$ and $C$ around a point charge $q$ . The potential difference $V_{A} - V_{B} = V_{B} - V_{C}$ . If $t_{1}$ and $t_{2}$ be the distances between them, then :

In a certain region, electric field E exist along the x-axis which is uniform. Given $A B = 23$ m and $B C = 4$ m. Point A, B and C are in xy plane. Find the potential difference $V_{A} - V_{B}$ between the points A and B :

The electric field and the electric potential at a point are E and V respectively. Then, the incorrect statements are :

Revise with Concepts

Equipotential Lines And Equipotential Surfaces

Figure shows three points A, B and C in a region of uniform electric field E. The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Here VA​,VB​ and VC​ represents the electric potential at point A, B and C respectively.

VA​=VB​=VC​

VA​=VB​>VC​

VA​=VB​<VC​

VA​>VB​=VC​

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface. So, VA​=VB​ and VB​>VC​

A, B and C are three points in a uniform electric field. The electric potential is :

V0​ is the potential at the origin in an electric field. E=Ex​i−Ey​j​. The potential at the point (x,y) is:

Figure shows three spherical and equipotential surfaces A, B and C around a point charge q. The potential difference VA​−VB​=VB​−VC​. If t1​ and t2​ be the distances between them, then :

In a certain region, electric field E exist along the x-axis which is uniform. Given AB=23​ m and BC=4 m. Point A, B and C are in xy plane. Find the potential difference VA​−VB​ between the points A and B :

The electric field and the electric potential at a point are E and V respectively. Then, the incorrect statements are :

Revise with Concepts

Equipotential Lines And Equipotential Surfaces

Figure shows three points A, B and C in a region of uniform electric field $E$ . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Here $V_{A}, V_{B}$ and $V_{C}$ represents the electric potential at point A, B and C respectively.

$V_{A} = V_{B} = V_{C}$

$V_{A} = V_{B} > V_{C}$

$V_{A} = V_{B} < V_{C}$

$V_{A} > V_{B} = V_{C}$

As we know the electrical lines of force always travel from higher potential to lower potential and lines of forces are perpendicular to the equipotential surface. So, $V_{A} = V_{B}$ and $V_{B} > V_{C}$

$V_{0}$ is the potential at the origin in an electric field. $E = E_{x} i - E_{y} j$ . The potential at the point (x,y) is:

Figure shows three spherical and equipotential surfaces $A$ , $B$ and $C$ around a point charge $q$ . The potential difference $V_{A} - V_{B} = V_{B} - V_{C}$ . If $t_{1}$ and $t_{2}$ be the distances between them, then :

In a certain region, electric field E exist along the x-axis which is uniform. Given $A B = 23$ m and $B C = 4$ m. Point A, B and C are in xy plane. Find the potential difference $V_{A} - V_{B}$ between the points A and B :