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Correct option is D)

From the given graph, $V(4,1)=2V$ and $V(6,1)=6V$

Thus, $∂x∂V =6−4V(6,1)−V(4,1) =26−2 =2V/cm=200V/m$

Thus, $E_{x}=−∂x∂V =−200V/m$

From the given graph, $V(6,2)=2V$ and $V(6,1)=6V$

Thus, $∂y∂V =2−1V(6,2)−V(6,1) =−4V/cm=−400V/m$

$∴$ $E_{y}=−∂y∂V =400V/m$

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