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Dimensional Analysis

Question

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Planck's constant has dimensions ________

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Solution

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$E = h υ$
$h \to$ planck's constant
$υ \to T^{- 1}$
$E \to M L^{2} T^{- 2}$
So, $M L^{2} t^{- 2} = h . T^{- 1}$
$h \to M L^{2} T^{- 1}$

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