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Operations on Rational Numbers

Question

Fill in the blanks:
$$-12 + \left (\dfrac {7}{12} + \dfrac {-9}{11}\right ) = \left (12 + \dfrac {7}{12}\right ) + (....)$$.

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Solution

Verified by Toppr

As we all know associative property states, $$(a + b) + c = a + (b + c)$$
We can simply solve by using the property
$$\therefore -12 + \left (\dfrac {7}{12} + \dfrac {-9}{11}\right ) = \left (12 + \dfrac {7}{12}\right ) + \left (\dfrac {-9}{11}\right )$$.

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Similar Questions

Q1

Fill in the blanks:
$$-12 + \left (\dfrac {7}{12} + \dfrac {-9}{11}\right ) = \left (12 + \dfrac {7}{12}\right ) + (....)$$.

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Q2

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(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

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Q3

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$___+ 3 \frac{1}{4} = 7 \frac{11}{12}$

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Q4

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\begin{matrix} 14 & 6 & (50) 11 & 9 & (92) 12 & 7 & (-) \end{matrix}

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Q5

Fill in the blank.

[13 + (- 12)] +

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= 13 + [(- 12) + (- 7)]

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