Fill in the blanks-dfrac-7-9-3- Hence the of the numerator and denominator so obtained-

Question

Toppr Admin · Accepted Answer

Correct option is A- 43-dfrac-7-9- - x - 3-Rightarrow x - -dfrac-7-9-3 -Rightarrow x - -dfrac-7-3-times 9-9-Rightarrow x - -dfrac-7 - 27-9-Rightarrow x - -dfrac-34-9-

Numerator	$7$
Denominator	$9$

Fill in the blanks:
$$\dfrac{-7}{9}+......=3$$. Hence find the sum of the numerator and denominator so obtained.

Correct option is A. 43
$$\dfrac{-7}{9} + x = 3$$

$$\Rightarrow x = \dfrac{7}{9}+3 $$

$$\Rightarrow x = \dfrac{7+3\times 9}{9}$$

$$\Rightarrow x = \dfrac{7 + 27}{9}$$

$$\Rightarrow x = \dfrac{34}{9}$$

Fill in the blanks:$$\dfrac{-7}{9}+......=3$$. Hence find the sum of the numerator and denominator so obtained.

Correct option is A. 43$$\dfrac{-7}{9} + x = 3$$$$\Rightarrow x = \dfrac{7}{9}+3 $$$$\Rightarrow x = \dfrac{7+3\times 9}{9}$$$$\Rightarrow x = \dfrac{7 + 27}{9}$$$$\Rightarrow x = \dfrac{34}{9}$$

Fill in the blanks:
$$\dfrac{-7}{9}+......=3$$. Hence find the sum of the numerator and denominator so obtained.

Correct option is A. 43
$$\dfrac{-7}{9} + x = 3$$

$$\Rightarrow x = \dfrac{7}{9}+3 $$

$$\Rightarrow x = \dfrac{7+3\times 9}{9}$$

$$\Rightarrow x = \dfrac{7 + 27}{9}$$

$$\Rightarrow x = \dfrac{34}{9}$$