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Question

Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.
(i) 14, 1 (ii) 2,13 (iii) 0,5
(iv) 1,1 (v) 14,14 (vi) 4,1

Solution
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(i) 14, -1

Using the quadratic equation formula,
x2(Sum of root)x+(Product of root)=0
Substitute the value in the formula, we get
x214x1=0
4x2x4=0

(ii) 2,13

Using the quadratic equation formula,
x2(Sum of root)x+(Product of root)=0
Substitute the value in the formula, we get
x22x+13=0
Multiply by 3 to remove denominator,
3x232x+1=0

(iii) 0, 5

Using the quadratic equation formula,
x2(Sum of root)x+(Product of root)=0
Substitute the value in the formula, we get
x20x+5=0
x2+5=0

(iv) 1, 1

Using the quadratic equation formula,
x2(Sum of root)x+(Product of root)=0
Substitute the value in the formula, we get
x21x+1=0
x2x+1=0

(v) 14,14

Using the quadratic equation formula,
x2(Sum of root)x+(Product of root)=0
Substitute the value in the formula, we get
x214x+14=0
Multiply by 4
4x2+x+1=0
(vi) 4, 1

Using the quadratic equation formula,
x2(Sum of root)x+(Product of root)=0
Substitute the value in the formula, we get
x24x+1=0

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