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Question

Find a rational number exactly halfway between:
$$\dfrac{1}{6}$$ and $$\dfrac{1}{9}$$

Solution
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As we know that
exactly halfway between two rational numbers is $$\dfrac{a+b}{2}$$
Rational numbers are $$\dfrac{1}{6}$$and $$\dfrac{1}{9}$$
Here, $$a=\dfrac{1}{6}$$and $$b=\dfrac{1}{9}$$
$$\therefore
\dfrac{a+b}{2}=\dfrac{\dfrac{1}{6}+\dfrac{1}{9}}{2}$$
$$=\dfrac{\dfrac{3+2}{18}}{2}$$
$$=\dfrac{5}{18\times2}$$

$$=\dfrac{5}{36}$$
Therefore, the exactly halfway between $$\dfrac{1}{6}$$and
$$\dfrac{1}{9}$$is $$\dfrac{5}{36}.$$

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