Find a relation between x and y such that the point (x,y) is equidistant from the points (7,1) and (3,5).
Let P(x,y) be equidistant from the points A(7,1) and B(3,5).
AP=BP
AP2=BP2
(x−7)2+(y−1)2=(x−3)2+(y−5)2
x2−14x+49+y2−2y+1=x2−6x+9+y2−10y+25
x−y=2