Find Energy of one mole proton if λ for photon is 331˙A.
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Solution
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Wavelength of photon =331A∘
(λ)=331×10−10m
Energy of one photon E=hcλ=6.62×10−34×3×1083.31×10−10=6×10−16J
Energy of one mole of protons =E×NA=6×10−16×6.023×1023=36.138×107≈3.6×108
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