Find equation of line passing through the points (−1,1) and (2,−4).
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Solution
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We know that the equation of line passing through points(x1,y1) and (x2,y2) is y−y1=y2−y1x2−x1(x−x1) Therefore equation of line passing through points (1,1) and (2,−4) is (y−1)=−4−12+1(x+1) ⇒(y−1)=−53(x+1) ⇒3(y−1)=−5(x+1) ⇒3y−3=−5x−5 ⇒5x+3y+2=0
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