Find equation of the line passing through the point (−4,3) with slope 12
We know that the equation of line passing through point (x0,y0) whose slope is m is
(y−y0)=m(x−x0)
Thus the equation of line passing through the point (−4,3) whose slope is 12 is,
(y−3)=12(x+4)
⇒2(y−3)=(x+4)
⇒x−2y+10=0