Question

Find equivalent capacity between A and B if capacity of each cap. is $2\mu F$.

Answer 1

Take point ${}^{\prime }{C}^{\prime }$ and ${}^{\prime }{D}^{\prime }$

Redraw the circuit.

Now, $C_2||C_3||C_4$

Equivalent $C_6$ of $C_2||C_3||C_4=2+2+2=6$

Now,

$C_1||C_6||C_5$ are in series.

$\begin{array}{c}\frac{1}{C_{eq}ofcircuit}=\frac{1}{2}+\frac{1}{6}+\frac{1}{2}=\frac{2+1+3}{6}=\frac{7}{6}\\ C_{eq}=\frac{6}{7}\end{array}$