Find equivalent capacity between A and B if capacity of each cap. is $2 μ F$ .

Question

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Answer 1

Take point $^{'} C^{'}$ and $^{'} D^{'}$
Redraw the circuit.
Now, $C_{2} ∣ ∣ C_{3} ∣ ∣ C_{4}$
Equivalent $C_{6}$ of $C_{2} ∣ ∣ C_{3} ∣ ∣ C_{4} = 2 + 2 + 2 = 6$
Now,
$C_{1} ∣ ∣ C_{6} ∣ ∣ C_{5}$ are in series.
$\frac{1}{C _{e q} o f c i r c u i t} = \frac{1}{2} + \frac{1}{6} + \frac{1}{2} = \frac{2 + 1 + 3}{6} = \frac{7}{6} C_{e q} = \frac{6}{7}$

Answer 2

Take point

^{'} C^{'}

and

^{'} D^{'}

Redraw the circuit.

Now,

C_{2} ∣ ∣ C_{3} ∣ ∣ C_{4}

Equivalent

C_{6}

of

C_{2} ∣ ∣ C_{3} ∣ ∣ C_{4} = 2 + 2 + 2 = 6

Now,

C_{1} ∣ ∣ C_{6} ∣ ∣ C_{5}

are in series.

\frac{1}{C _{e q} o f c i r c u i t} = \frac{1}{2} + \frac{1}{6} + \frac{1}{2} = \frac{2 + 1 + 3}{6} = \frac{7}{6} C_{e q} = \frac{6}{7}